3n^2+5=n^2-7n-18

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Solution for 3n^2+5=n^2-7n-18 equation: 



3n^2+5=n^2-7n-18

We move all terms to the left:

3n^2+5-(n^2-7n-18)=0

We get rid of parentheses

3n^2-n^2+7n+18+5=0

We add all the numbers together, and all the variables

2n^2+7n+23=0

a = 2; b = 7; c = +23;
Δ = b2-4ac
Δ = 72-4·2·23
Δ = -135
Delta is less than zero, so there is no solution for the equation

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